If you work out the mean, median, mode and range of $2, 5, 5, 6, 7$, you'll notice something interesting...

The mean, mode, median, and range of this set are all $5$.

**Can you find other sets of five positive whole numbers where Mean = Median = Mode = Range?**

Charlie found that $50, 100, 100, 100, 150$ had Mean = Median = Mode = Range = 100

Alison found that $40, 100, 100, 120, 140$ also had Mean = Median = Mode = Range = 100

**How many sets of five positive whole numbers are there with Mean = Median = Mode = Range = 100?**

## Comments

### n = any number

n = any number

first number 2 * n

second number 5 * n

third number 5 * n

fourth number 6 * n

fifth number 7 * n

To get SOME of the answers.

### n = any number

2n, 5n, 5n, 6n, 7n provides a "family" of solutions that satisfy the criteria.

Can you now find some different "families" that also satisfy the criteria?

### المتوسطات متساوية

**Case 1: 50, 100, 100, 100, 150 **

**Case 2: X1 < X2 < 100 < 100 < X3**

$50 < X1 < X2 < 100$

and $150 < X3 < 200$

and $X3 - X1 = 100$

and $2X3 + X2 = 400$

There are 16 possibilities:

X1 = 52 X2 = 96 X 3= 152

.

.

.

X1 = 66 X2 = 68 X3 = 166

**Case 3: X1 < 100 < 100 < X2 < X3**

$0 < X1 <50$

and $100 < X2 < X3 <150$

and $X3 - X1 = 100$

and $2X3 + X2 = 400$

There are 16 possibilities:

X1 = 35 X2 = 130 X 3= 135

.

.

.

X1 = 49 X2 = 102 X3 = 149

Therefore there are 33 possibilities altogether.

### Sets for 100

From Penndale Middle School (Lansdale, PA) – Chi Alpha Mu (Math Club)

Knowing that MEAN = MEDIAN = MODE = RANGE = 100,

For any set of five positive whole numbers: A, B, C, D, E

C = 100 (to account for the median = 100)

E = 100 + A (to account for the range = 100)

B or D = 100 (to account for the mode = 100)

Let D = 100, then (A + B + 100 + 100 + (100+A)) / 5 = 100

Simplified, B = 200 - 2A

With this it was found that:

34 ≤ A ≤ 66

Therefore there are 66 – 33 = 33 sets of five positive whole numbers with MEAN = MEDIAN = MODE = RANGE = 100