If you work out the mean, median, mode and range of $2, 5, 5, 6, 7$, you'll notice something interesting...
The mean, mode, median, and range of this set are all $5$.
Can you find other sets of five positive whole numbers where Mean = Median = Mode = Range?
Charlie found that $50, 100, 100, 100, 150$ had Mean = Median = Mode = Range = 100
Alison found that $40, 100, 100, 120, 140$ also had Mean = Median = Mode = Range = 100
How many sets of five positive whole numbers are there with Mean = Median = Mode = Range = 100?
Comments
n = any number
n = any number
first number 2 * n
second number 5 * n
third number 5 * n
fourth number 6 * n
fifth number 7 * n
To get SOME of the answers.
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n = any number
2n, 5n, 5n, 6n, 7n provides a "family" of solutions that satisfy the criteria.
Can you now find some different "families" that also satisfy the criteria?
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المتوسطات متساوية
Case 1: 50, 100, 100, 100, 150
Case 2: X1 < X2 < 100 < 100 < X3
$50 < X1 < X2 < 100$
and $150 < X3 < 200$
and $X3 - X1 = 100$
and $2X3 + X2 = 400$
There are 16 possibilities:
X1 = 52 X2 = 96 X 3= 152
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X1 = 66 X2 = 68 X3 = 166
Case 3: X1 < 100 < 100 < X2 < X3
$0 < X1 <50$
and $100 < X2 < X3 <150$
and $X3 - X1 = 100$
and $2X3 + X2 = 400$
There are 16 possibilities:
X1 = 35 X2 = 130 X 3= 135
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X1 = 49 X2 = 102 X3 = 149
Therefore there are 33 possibilities altogether.
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Sets for 100
From Penndale Middle School (Lansdale, PA) – Chi Alpha Mu (Math Club)
Knowing that MEAN = MEDIAN = MODE = RANGE = 100,
For any set of five positive whole numbers: A, B, C, D, E
C = 100 (to account for the median = 100)
E = 100 + A (to account for the range = 100)
B or D = 100 (to account for the mode = 100)
Let D = 100, then (A + B + 100 + 100 + (100+A)) / 5 = 100
Simplified, B = 200 - 2A
With this it was found that:
34 ≤ A ≤ 66
Therefore there are 66 – 33 = 33 sets of five positive whole numbers with MEAN = MEDIAN = MODE = RANGE = 100
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